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38x^2+99x+63=0
a = 38; b = 99; c = +63;
Δ = b2-4ac
Δ = 992-4·38·63
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-15}{2*38}=\frac{-114}{76} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+15}{2*38}=\frac{-84}{76} =-1+2/19 $
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